3 Déc
2011
3 Déc
'11
13:14
On Fri, 2011-12-02 at 19:01 -0800, Andrew Lentvorski wrote:
I think that expansion is wrong. IIRC, IEEE754 specifies that NaNs are unordered. Consequently, I think that both (nan1 == nan2) and (nan1 != nan2) must return false.
That's true in C, and in Gambit
(= nan1 nan2) => #f
because it conforms to IEEE floating-point equality.
But eqv? compares floating-point numbers bitwise in Gambit, and I agree with that behavior.
Brad