7 Mar
2014
7 Mar
'14
15:11
Why this result of (haxor-exact->inexact 0), just curious, does the RNRS dictate this? (define (haxor-exact->inexact n) (* n 1.0)) (haxor-exact->inexact -1) => -1*.* (haxor-exact->inexact 0) => 0 (haxor-exact->inexact 1) => 1*.*