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...another question: what is the correct result of (case ".ab" ((".ab") 1) (else 2)) case use eqv?; two string with the same contents may not be eqv?. Brad
another question: what is the correct result of (case ".ab" ((".ab") 1) (else 2)) case use eqv?; two string with the same contents may not be eqv?.
another question: what is the correct result of
(case ".ab" ((".ab") 1) (else 2)) case use eqv?; two string with the same contents may not be eqv?.
Brad
Ok, then my code is now rewritten as (case (string->symbol ".ab") ((.ab) 1) (else 2)) :) Christoph
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