18 Déc
2015
18 Déc
'15
06:49
Marc, Is there an outer extent on wills' applicability - why don't the second two gsc runs say OUT on termination? Thanks, Adam $ gsc
(define a (box 1)) (make-will a (lambda (v) (print "OUT.\n") (force-output))) #<will #2> (##gc) (set! a #f) (##gc) OUT. ,q $ gsc (define a (box 1)) (make-will a (lambda (v) (print "OUT.\n") (force-output))) #<will #2> ,q $ gsc (make-will (box 1) (lambda (v) (print "OUT.\n") (force-output))) #<will #2> ,q $