[gambit-list] Returning a byte array from C
vijay.the.lisper at gmail.com
Wed Sep 25 04:48:39 EDT 2013
Thanks for reviewing my code.
I have updated the C function as follows:
int read_bytes (int fd, size_t count, ___SCMOBJ data_vect)
void *data = malloc (count);
if (data == NULL)
result = -1;
result = read (fd, data, count);
if (result > 0)
memcpy (___BODY (data_vect), data, result);
A call from scheme will look like:
(read-bytes fd count (make-u8vector count 0))
I suppose now I don't have to worry about leaks or heap-overflow-exceptions.
On Tue, Sep 24, 2013 at 8:52 PM, Marc Feeley <feeley at iro.umontreal.ca>wrote:
> On 2013-09-23, at 11:14 AM, Vijay Mathew <vijay.the.lisper at gmail.com>
> > The following C function is a wrapper for the `read' system call.
> > It returns a pair that contains the number of bytes read and the data.
> > Is this the right way to initialize a u8vector from C?
> There are a few things I would do differently, such as heap overflow
> checking. But for the particular task of providing a wrapper to the read
> system call I would use a different interface. Why don't you allocate the
> buffer in Scheme before calling read? That would simplify the C code
> (avoiding GC issues) and would be more efficient.
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