[gambit-list] port fun
lowlycoder at huoyanjinjing.com
Mon Oct 12 04:15:10 EDT 2009
I have some pre-existing library code I'm dealing with, which I can
pass it an port (that the library will send output to).
Is it possible to create a function foo, so that
(foo output-port1 output-port2)
will return me a output-port-magic
s.t. when anything iw written to output-port-magic, it's written to
both output-port1 and output-port2?
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