[gambit-list] port fun

lowly coder lowlycoder at huoyanjinjing.com
Mon Oct 12 04:15:10 EDT 2009


  I have some pre-existing library code I'm dealing with, which I can
pass it an port (that the library will send output to).

Is it possible to create a function foo, so that

(foo output-port1 output-port2)

will return me a output-port-magic

s.t. when anything iw written to output-port-magic, it's written to
both output-port1 and output-port2?


More information about the Gambit-list mailing list