> > another question: what is the correct result of
> >
> > (case ".ab" ((".ab") 1) (else 2))
> case use eqv?; two string with the same contents may not be eqv?.
>
> Brad
>
>
Ok, then my code is now rewritten as
(case (string->symbol ".ab") ((.ab) 1) (else 2))
:)
Christoph