This is the definition  in C:

typedef enum _cairo_format {
    CAIRO_FORMAT_INVALID   = -1,
    CAIRO_FORMAT_ARGB32    = 0,
    CAIRO_FORMAT_RGB24     = 1,
    CAIRO_FORMAT_A8        = 2,
    CAIRO_FORMAT_A1        = 3,
    CAIRO_FORMAT_RGB16_565 = 4
} cairo_format_t;


AFAIK, bindings in Gambit usually deal with this as an integer, but with C++ enabled, conversion is needed.




2012/2/5 Mikael <mikael.rcv@gmail.com>


2012/2/5 Álvaro Castro-Castilla <alvaro.castro.castilla@gmail.com>
Hi!

I open a new thread, because this is a deeper issue than the C++ enums conversion problem.

When I declare this:

(define CAIRO_FORMAT_RGB24 ((c-lambda () cairo-format-t "___result = CAIRO_FORMAT_RGB24;")))

or:
(define CAIRO_FORMAT_RGB24 (c-lambda () cairo-format-t "___result = CAIRO_FORMAT_RGB24;"))
and then call
(CAIRO_FORMAT_RGB24)

my program segfaults. It seems that just executing that c-lambda, returning an enum, fails. The enum is defined as:  (c-define-type cairo-format-t "cairo_format_t")

Ouch - your declaration makes Gambit identify, I think, cairo_format_t as a C structure, and tries to copy its contents fully. Hmm. If this is not how it really is, do (c-define-type cairo-format-t integer) or sth?

I don't understand why this segfaults: 1) I'm declaring the type 2) I'm returning the proper type. What's the problem?


Best regards,

Álvaro

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