Steve,

maybe I can help.


##decompile retrieve the source code of a procedure (if available):

> (##decompile (##lambda () test))
(lambda () test)

If you change the name-space with:

> (namespace ("test-namespace#"))

decompile yields:

> (##decompile (##lambda () test))
(lambda () test-namespace#test)

That means you have to strip the symbol suffix `test`
to get the name-space.

If you use the empty symbol, denoted by ||, you get the name-space
symbol directly:

> (##decompile (##lambda () ||)) 
(lambda () test-namespace#)

With this information, one can define the following macro:

> (define-macro (##current-namespace) (##symbol->string (eval (##quote (##caddr (##decompile (##lambda () ||)))))))          

For e newly started gsi you get:

> (##current-namespace)                                                                                         
""

If you change the name-space you get:

> (namespace ("test-namespace#"))
> (##current-namespace)                                                                                         
"test-namespace#"


HTH,

Gerald


Am 28.07.2016 um 19:12 schrieb Steve Graham:
Marc,
   Could you explain this a bit?

Thanks, Steve

      From: Marc Feeley <feeley@iro.umontreal.ca>
 To: Duncan Watts <djmwatts@gmail.com> 
Cc: Gambit-list@iro.umontreal.ca
 Sent: Thursday, July 28, 2016 4:22 AM
 Subject: Re: [gambit-list] Current namespace at the repl
   
A bit of a hack... Try:

(##caddr (##decompile (##lambda () ||)))

You can define a macro based on that idea.

Marc


On Jul 28, 2016, at 12:09 PM, Duncan Watts <djmwatts@gmail.com> wrote:

Is there a function (or would it be easy to access the internals to write one) to find out what the currently active namespace is at the repl. Ie after entering a few (namespace ("foo#")) expressions it would be nice to be able check what the current namespace is with eg (current-namespace) --> "foo#"

Thanks
Duncan
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